Selective command line parameters.


 
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# 1  
Old 07-17-2012
Selective command line parameters.

Hi,

I have a script which has 3 command line parameters.But sometimes it will also take 2 command line parameters or 1.How to do it?

I am using $1,$2... to specify the command line parameters.

The script which i have written is given below.
Code:
#!/bin/sh
echo "database="$1
echo "parameter="$2
echo "table="$3
echo "1st parameter:$1"
echo "2nd parameter:$2"
echo "3rd parameter:$3"

The will not require all the 3 parameters to run each time.Sometimes it will take 2 and sometime 1 also.

Please suggest how to do it.

Thanks

Last edited by Franklin52; 07-17-2012 at 05:00 PM.. Reason: Please use code tags for data and code samples, thank you
# 2  
Old 07-17-2012
You could just check the availability of each of them and assign it to other variables.

like,
Code:
 if [ "$1" != "" ]; then
echo "database=NO_OPTION_AVAILABLE"
else
echo "database="$1
fi

Smilie
# 3  
Old 07-17-2012
Thats ok.
But the problem is while executing the script.
suppose i do not want to pass parameter 1 and 2,need to pass only parameter 3.

How to do that?

if a mention only one then it will take it as the 1st parameter.Smilie
# 4  
Old 07-17-2012
Similarly, you may have to pass another parameter which indicates what all parameters to select first! right??
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