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perl one-liner to get yesterday's date in format dd-MMM-yy (i.e. 01-JAN-12)

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Top Forums Shell Programming and Scripting perl one-liner to get yesterday's date in format dd-MMM-yy (i.e. 01-JAN-12)
# 1  
Old 07-15-2012
perl one-liner to get yesterday's date in format dd-MMM-yy (i.e. 01-JAN-12)
I have the following perl one-liner to get yesterday's date, but I would like it in the form of dd-MMM-yy (for example: 01-JAN-12). Can someone alter the below code so I get the format I want? Also, could someone also give me a line for dd-Mmm-yy (for example 01-Jan-12)?

Code:
Code:
YEST=`perl -w -e '@yest=localtime(time-86400);printf "%d%.2d%.2d",$yest[5]+1900,$yest[4]+1,$yest[3];'`

Last edited by radoulov; 07-16-2012 at 10:09 AM..
# 2  
Old 07-16-2012
Code:
perl -e 'use POSIX qw(strftime);$now_string = strftime "%e-%b-%Y", localtime(time-86400); print $now_string,"\n";'

This User Gave Thanks to pravin27 For This Post:
thibodc
# 3  
Old 07-16-2012
Thanks so much...I'll give it a try today!
# 4  
Old 07-16-2012
Just nitpicking:
Code:
root# date -s '12 Mar 2012 00:10'
Mon Mar 12 00:10:00 EDT 2012
$ perl -MPOSIX -le'print strftime "%e-%b-%Y",localtime(time-86400)'
10-Mar-2012

$ perl -MPOSIX -le'@a=localtime;--$a[3];print strftime "%e-%b-%Y",@a'
11-Mar-2012

Last edited by binlib; 07-16-2012 at 11:58 AM.. Reason: Added fix
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