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Shell Programming and Scripting

File Formatting

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# 1  
Old 07-15-2012
File Formatting
Hi,
I have requirement to format the file.My input file tab(\t) saperated.
File format is:-

Code:
93      WARNING Sat Mar 17 20:31:59 2012
        Sequential_File_0,0: Missing record delimiter "\r\n", saw EOF instead
94      WARNING Sat Mar 17 20:31:59 2012
        Sequential_File_0,0: Import warning at record 0.
121     WARNING Sun Jul 15 00:37:10 2012
        Sequential_File_0,0: Missing record delimiter "\r\n", saw EOF instead
122     WARNING Sun Jul 15 00:37:10 2012
        Sequential_File_0,0: Import warning at record 0.

I want to replace \n\t with \t so that my output file will look like this:-

Code:
93      WARNING Sat Mar 17 20:31:59 2012   Sequential_File_0,0: Missing record delimiter "\r\n", saw EOF instead
94      WARNING Sat Mar 17 20:31:59 2012   Sequential_File_0,0: Import warning at record 0.
121     WARNING Sun Jul 15 00:37:10 2012    Sequential_File_0,0: Missing record delimiter "\r\n", saw EOF instead
122     WARNING Sun Jul 15 00:37:10 2012    Sequential_File_0,0: Import warning at record 0.

I tried to replace it using tr command,but it seems its replacing all \n from file.
Code:
tr '\n\t' '\t' < file1.txt> file4.txt

Finally i have done this by:-
Code:
grep "WARNING" File.txt > File1.txt
grep -v "WARNING" File.txt>File2.txt
paste File1.txt File2.txt

But it seems this is not a correct way because i dont know which string i need to grep.
Can anyone help.
Thanks
Last edited by Scrutinizer; 07-15-2012 at 06:46 AM.. Reason: quote tags => code tags
# 2  
Old 07-15-2012
Code:
perl -ne 'if (!/^\t/){chomp;$rec=$_;}else{$rec.=$_;print $rec;}' tmp.dat

# 3  
Old 07-15-2012
Try (gawk, mawk, bwk):
Code:
awk 1 RS='\n\t' infile

POSIX awk:
Code:
awk 'END{print RS} {$0=(/^\t/?x:RS) $0}1' ORS= infile


--
If there is always a sequence of two lines:
Code:
awk '{ORS=(!/^\t/)?x:RS}1' infile

--
sed:
Code:
sed '/^[0-9]/{N;s/\n//;}' infile

or perhaps just
Code:
sed 'N;s/\n//' infile

This User Gave Thanks to Scrutinizer For This Post:
prasson_ibm
# 4  
Old 07-15-2012
Quote:
Originally Posted by Scrutinizer
Try (gawk, mawk, bwk):
Code:
awk 1 RS='\n\t' infile

POSIX awk:
Code:
awk 'END{print RS} {$0=(/^\t/?x:RS) $0}1' ORS= infile


--
If there is always a sequence of two lines:
Code:
awk '{ORS=(!/^\t/)?x:RS}1' infile

--
sed:
Code:
sed '/^[0-9]/{N;s/\n//;}' infile

or perhaps just
Code:
sed 'N;s/\n//' infile

Hi,

Thanks for your reply!

Quote:
sed 'N;s/\n//' infile
code is working for me.Smilie

Can you please explain how its formatting the file..

Thanks
# 5  
Old 07-15-2012
Hi, it just appends every second line (N) and then removes the newline character (s/\n//)..

So on line 1, line 2 gets appended, on line 3 line 4, etc...
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