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Shell Programming and Scripting

Create random number

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# 1  
Old 07-12-2012
Create random number
Hi,


I'm trying to create a script that will print random numbers with length of three.

Below is the expected out.

928-377-899
942-458-310
951-948-511
962-681-415
995-161-708
997-997-209

thanks
# 2  
Old 07-12-2012
this generates random number as u expected.. but i am not sure about its uniqueness. Below command gives you 7 results u can change the i for how much you want...

Code:
awk 'BEGIN { for (i = 1; i <= 7; i++) print ( int(1000 * rand()) "-" int(1000 * rand()) "-" int(1000 * rand())) }'

# 3  
Old 07-12-2012
You need to use srand() first..
# 4  
Old 07-12-2012
Perhaps seed the random number generator with srand() or you may get the same random numbers for each run...
Code:
$ awk 'BEGIN { for (i = 1; i <= 7; i++) print ( int(1000 * rand()) "-" int(1000 * rand()) "-" int(1000 * rand())) }'
237-291-845
152-585-193
810-173-484
151-366-491
910-265-893
220-631-571
332-104-502

$ awk 'BEGIN { for (i = 1; i <= 7; i++) print ( int(1000 * rand()) "-" int(1000 * rand()) "-" int(1000 * rand())) }'
237-291-845
152-585-193
810-173-484
151-366-491
910-265-893
220-631-571
332-104-502

$ awk 'BEGIN { for (i = 1; i <= 7; i++) print ( int(1000 * rand()) "-" int(1000 * rand()) "-" int(1000 * rand())) }'
237-291-845
152-585-193
810-173-484
151-366-491
910-265-893
220-631-571
332-104-502

$ awk 'BEGIN { srand(); for (i = 1; i <= 7; i++) print ( int(1000 * rand()) "-" int(1000 * rand()) "-" int(1000 * rand())) }'
676-830-414
258-178-379
76-885-517
508-900-613
718-789-553
880-689-744
142-8-667

$

# 5  
Old 07-12-2012
Code:
[root@node3 ~]# for i in {0..5}; do echo $((RANDOM%900+100))-$((RANDOM%900+100))-$((RANDOM%900+100)); done
305-222-530
832-784-382
460-325-680
598-111-820
314-888-186
640-554-449

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