Shell Programming and Scripting

Hi guys,

I need to find multiple strings within files under a directory and secondly, to count how many files are there with these strings.

At present, i am able to do this in order to find one string (for example "abc"):

Code:

find <path> -exec grep "abc" {} /dev/null \;

Now for example, i need to find "abc" and "cde" as well, then how would i do this? And also how can i count how many files are there that contain "abc" and "cde"?


regards.

Moderator's Comments:

Please use code tags next time for your code and data.

If you want to count the number of lines on which one or more of these strings occur

Code:

for i in $(find /path/to/dir) ; do grep -E '(abc|cde)' ;done | wc -l

If you just want a count of files in which one of the strings occurs

Code:

for i in $(find /path/to/dir) ; do echo $i:$(grep -E '(abc|cde)') ;done |cut -d \: -f1|uniq| wc -l

Thanks for the reply.

I tried the first for loop, it's giving below error:
syntax error: `$' unexpected

I've been able to find the files which contain the 2 strings as follows:

Code:

find . -type f |xargs grep -l 'abc' | xargs grep -l 'cde'

I'm still looking for a way to find the count, i.e, the number of files that contain both strings.

regards.