Awk: Need help replacing a specific column in a file by part of a column in another file
Hi,
I have two input files as
Also, array of valid values can be hardcoded like [W,WT]
SO basically, if the column2 of file1 matches any record's column1 in file2, then replace that column2 in file1 by a part of column2 from file2.
TO obtain this part I need to split column2 in file2 using "-" operator and match the results against an array to determine valid values.
For the records not matching above criteria, they should NOT be displayed in the output.
I am new to shell scripting so would appreciate any help.
I have been trying since a couple of days and have been able to replace the entire column using
However, haven't been able to get the part of the column requirement working.
Last edited by methyl; 07-10-2012 at 07:54 PM..
Reason: please use code tags ; layout ;awk in thread title
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I would like to ask your expertise to remove specific column no. 8 in the below file using but I don't have an idea on how to simply do this using awk command. Appreciate your help in advance.
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ABC 1 1XC
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CCC 1 3XC
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Expected output file:
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If 2nd column of file1 has pattern foo1@a, find the matching 1st column in file2 & replace 2nd column of file1 with file2's value.
file1
abc_1 foo1@a ....
abc_1 soo2@a ...
def_2 soo2@a ....
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I will really appreciate if you kindly lookinto my requirement below and provide me a solution
First file format test1.txt
qq ww rr tt ee ff
qq ww rr tt ee ff
Second file format text2.txt
aa
aa
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Hi, I have two input files.
File1:
ID Name Place
1-234~name1~Newyork
1-34~name2~Boston
1-2345~name3~Hungary
File1 is a variable length file where each column is seperated by delimitter "~".
File2:
ID Country
1-34<<11 SPACES>>USA<<7 spaces>>
1-234<<10 SPACES>>UK<<8 spaces>>
... (1 Reply)