Shell Programming and Scripting

What would be the easiest way to grep all files within a particular directory that match a partial filename? For example, searching all files that begin with "filename.txt" and are appended with the date they were created. I am using Ksh 88, btw.

grep "expression"

That's really what grep is for; please read the grep manpage.

What I would ideally like to do is perform a grep on all of the files, and if any of the search parameters are found, output both the filename and the line containing the parameter found. This is the default behaviour for grep, is it not? If no matches are found, I want to output an appropriate message.

I was thinking of something along the lines of:

Code:

if grep ${vString} filename.ext.* > /dev/null
then
    grep ${vString} filename.ext.*
else
    print "${vString} not found in ${instances[x]} filename.ext"
fi

Running that line of code twice seems wasteful, though. Can this be done without the duplication?

Try something like this:

Code:

#!/bin/ksh

for file in `ls -1 filename.ext.*`
do 
    result=`grep ${vString} $file`
    if [ $? -ne 0 ] ; then
        echo "${vString} not found in ${instances[x]} -- in $file"
    else
        echo "$file $result"    
    fi
done

-- not tested.