Shell Programming and Scripting

I'm using cygwin bash to submit scheduled tasks (kinda like cron jobs) in windows and the following script is giving me grief. I need to format the current time with leading zeros before 10AM for the hour field. In this example, I manually typed in "09:50" instead of using the `printf...` statement. Note, however, I get an error in my debug statement when I try to print out the the time. Why is it choking on '09'?

I assume the problem is the "printf" statement because I get that error message twice: once for every occurance of the printf statement (when I prevously had `printf` instead of "09:50"). Could the problem be the %s that windows needs inside the quoted strings? Is not bash supposed to ignore the contents of quoted strings?


I do not intend this to be an octal value!

Code:

h=`date +%H`
m=`date +%M`
let m=m+1
let h=h+0
echo `printf "%-2.2d:%-2.2d" $h $m`
schtasks /delete /tn "vgr_day_build"  /F
schtasks /create /tn "vgr_day_build" /tr "c:\Users\310064858\Documents\philips\bin\rick_croote_nightlyBuilds.bat siegfried_FireWall_01 >d:\views\buildlogs\vgr_day_build_%date:~-4,4%%date:~-10,2%%date:~-7,2%%time:~-11,2%%time:~-8,2%%time:~-5,2%%date:~0,3%.log 2>&1" /sc ONCE /st 09:51
/usr/bin/bash: line 3: let: 09: value too great for base (error token is "09")
/usr/bin/bash: line 4: printf: 09: invalid octal number
00:51
SUCCESS: The scheduled task "vgr_day_build" was successfully deleted.
SUCCESS: The scheduled task "vgr_day_build" has successfully been created.

You are correct, values starting with a leading zero (0) are interpreted as an octal. As the only values allowed in octal are {0..7}, an 8 or a 9 will cause the error message.

Workarounds include stripping the leading zero:

Code:

h="08"
h=`echo $h | sed 's/^0*//'`

or you can explicitly set the base when incrementing:

Code:

h="08"
h=$(( 10#$h + 1 ))

I've never seen that syntax for setting the base before, thanks.

What I've sometimes done is crammed a '1' on the front then subtracted 100