Shell Programming and Scripting

x=1
j=1
while [ $j -le 3 ]
do
..
....
....
while [ some condition]
do 
..
..
x=x+1
done
#inner most while loop ends here
done
#outer loop ends here

so my question is is there any way to access the value of x at outer loop which is set in inner loop 
here x=2 should be used at outer loop

x=1;
j=1;

while [[ $j -le 3 ]]
do
echo "$x  $j"

while [[ $x -le 2]]
do 
echo "$x             $j"
let x=x+1
done
done

echo "$x     -- $j"

This is my code
j=1
x=1
y=1
z=1

while [ $j -le 3 ]
do
   cat file | while read line

        do

        if [[ `echo $line | grep -i "UBBE"` ]];  then
        if [ $x -eq 1 ]; then
        echo $line | awk -F '[]U]' '/UBBE/ {print "U"$NF" "$1"]"}'
        x=`expr $x - $x`
         fi
        fi
        done

echo "Innermost $x $j"

j=`expr $j + 1`

done

#echo "In $x $j";

cat file | while read line
do
   :
done

while read line
do
   :
done < file