Shell Programming and Scripting

Thanks Vino for your help

My input file is as below

ISA~00~ ~00~ ~ZZ~12345 ~ZZ~54321 GS~SH~12345 ~54321
ST~86~000000007
BSN~00~0958
DTM~011~ET

And, when I ran the code above, the below results appeared

ISA~00~ ~00~ ~ZZ~12345 ~ZZ~54321 GS~SH~12345 ~54321
ST~86~000000007
BSN~00~0958
DTM~011~ET


My requirement is to get the first 2 or 3 characters like ISA, GS, ST, BSN and DTM. In this file, the special character is '~', but in other files it may vary.

Thanks,
AK

What shell and os are you using ?

Vino

This is what I got on my terminal

Code:

[~/temp]$ awk -F"[*~+]" '{print $1}' kum.txt 
ISA
ST
BSN
DTM

where kum.txt is

Code:

[~/temp]$ cat kum.txt 
ISA~00~ ~00~ ~ZZ~12345 ~ZZ~54321 GS~SH~12345 ~54321
ST~86~000000007
BSN~00~0958
DTM~011~ET

Vino

Hi Vino,

I am using SUN OS 5.8, and Korn Shell.

I am not getting the desired results.

Dont have any SunOS distro at my disposal.

Someone could please check it out.

Vino

whoa - the reason you're not getting the desired output is because you're not giving us the desired input

We'll need to know *all* the delimeters used, we can't make them up.

Cheers
ZB

Hi,

Vino is getting the desired output on his os and shell.

I can use the delimiters like * ~ + : <

Can anyone help??