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Use case insensitive variable in ksh shell scripting using sed or awk

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Top Forums Shell Programming and Scripting Use case insensitive variable in ksh shell scripting using sed or awk
# 8  
Old 06-18-2012
Quote:
Originally Posted by johnjs
Both the solutions are not working..

I tried
Code:
awk 'tolower($0) ~ /'$variable'/,/endpattern' filename

but is working only if we give the input variable in lowercase and the actual pattern in file is uppercase. i want to search the file for both uppercase and lowercase irrespective of the input case we are giving.
what is your output?

@Scrutinizer's code is correct to me..
because of this code converts to lower (or upper ) for any input (does not matter if it is lower case or upper)
and if it matches then write..

Code:
# cat file
Test
first
1
2
3
endpattern
Test1
Test2
FIRST
4
5
6
endpattern
Test3
Test4
FiRsT
1
2
3
endpattern
XXXXXX
XXXXXXXX

for exa your input variable "first"..
Code:
# awk 'toupper($0)~toupper(s),/endpattern/' s="first" file
first
1
2
3
endpattern
FIRST
4
5
6
endpattern
FiRsT
1
2
3
endpattern

for exa your input variable "FIRST"
Code:
# awk 'tolower($0)~tolower(s),/endpattern/' s="FIRST" file
first
1
2
3
endpattern
FIRST
4
5
6
endpattern
FiRsT
1
2
3
endpattern

if you use the solaris then you must try the with the nawk or /usr/xpg4/bin/awk
This User Gave Thanks to ygemici For This Post:
johnjs
# 9  
Old 06-18-2012
Lateral thought method: Find out the line numbers containing each case-insensitive match to $variable and use sed to display from that line number until the the next occurence of endpattern. Does not work if $pattern just contains a number.
Code:
cat -n file | grep -i "${variable}" | awk '{print $1}' | while read n
do
     sed -n "$n,/endpattern/ p" file
done

Grossly inefficient for large files and/or where there are many hits.
Last edited by methyl; 06-18-2012 at 11:05 AM.. Reason: layout and grammar
# 10  
Old 06-18-2012
Thanks Bakunin.. Please find the sample case below. if i have a file like below

FIRST:\
one
two
three
end:

second:\
one
two
three
end:

case 1: If i gave search variable as "first" then it should match and print the o/p like below

FIRST:\
one
two
three
end:

case 2: If i gave search variable as "SECOND" then also it should match and print the o/p like below

second:\
one
two
three
end:

case 3: If i gave search variable as "FIRST" then it should match and print the o/p like below

FIRST:\
one
two
three
end:

case 4: If i gave search variable as "second" then also it should match and print the o/p like below

second:\
one
two
three
end:
# 11  
Old 06-18-2012
Hi, I get:

Code:
$ variable=first; awk 'tolower($0)~tolower(s),/end:/' s="$variable" infile
FIRST:\
one
two
three
end:
$ variable=SECOND; awk 'tolower($0)~tolower(s),/end:/' s="$variable" infile
second:\
one
two
three
end:
$ variable=FIRST; awk 'tolower($0)~tolower(s),/end:/' s="$variable" infile
FIRST:\
one
two
three
end:
$ variable=second; awk 'tolower($0)~tolower(s),/end:/' s="$variable" infile
second:\
one
two
three
end:

What do you get?




--
On Solaris use /usr/xpg4/bin/awk rather than awk
This User Gave Thanks to Scrutinizer For This Post:
johnjs
# 12  
Old 06-18-2012
it works
awk 'tolower($0)~tolower(s),/endpattern/' s="FIRST" file

the baove comamd works..
thanks for all your help..
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