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# 1  
Old 06-13-2012
a question on grep
hi, I used grep "total packets" to filter a file and get the following results, what I want is to get the lines with only one "total packets", are there any methods? thanks!

Code:
    total packets: 131
     total packets:            55           total packets:            76      
    total packets: 127
     total packets:            55           total packets:            72      
    total packets: 152
     total packets:            68           total packets:            84      
    total packets: 9
     total packets:             5           total packets:             4      
    total packets: 9
     total packets:             5           total packets:             4      
    total packets: 41
     total packets:            22           total packets:            19      
    total packets: 130
     total packets:            35           total packets:            95      
    total packets: 84
     total packets:            31           total packets:            53      
    total packets: 9
     total packets:             5           total packets:             4      
    total packets: 10
     total packets:             6           total packets:             4

# 2  
Old 06-13-2012
seems like those lines with only one "total packets" starts from the beginning of the line, and there are no space.. In that case you could use ^ for beginning of the line

Code:
grep '^total packets' file

# 3  
Old 06-13-2012
If you mean total packets: 1

Try..

Code:
grep "total packets: 1$" file

---------- Post updated at 15:08 ---------- Previous update was at 15:01 ----------

If those might be on multiple lines.

Code:
grep -E "total packets:[[:blank:]]+1[[:blank:]]+" file

# 4  
Old 06-13-2012
awk
Hi,

Try this one,

Code:
awk '/total packets/{t=$0;c=gsub(/total packets/,"",t);if(c==1)print;}' file

Use this code instead of grep.

Cheers,
RangaSmilie
# 5  
Old 06-13-2012
Code:
grep 'total packets: [^ ]' file

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