Shell Programming and Scripting

Hi,

Thanks in Advance..

i have the following requirement, some one please help me..

An unix shell script has to pick up the file name from a folder as soon as that file comes into that folder.

Regards,
Alo

How about using a sleep ?

Code:

#! /bin/sh

while true
do
[ -f /path/to/the/new/file ] && echo "/path/to/the/new/file"
#sleep for 1 min
sleep 60
done

Vino

if time is critical ... use "sleep 1" instead to check every second ...

If you can have the check done every minute, the most efficient way is probably to schedule it via the crontab utility. Here's what your cron entry could look like:

* * * * * move_file.sh /the_dir/the_file

This entry would run a script (move_file.sh) every minute of every day. The script just needs to test the exeistence of the file and do whatever needs to be done with it.

HTH

Réal

Vino,

Thanks for your post.

i m using ksh shell script and tested the following file,

#! /bin/ksh

while true
do
[ -f /synchen/dtazv/fhu/sourcedir ] && echo "/synchen/dtazv/fhu/sourcedir"
#sleep for 1 min
sleep 60
done



the following error has been thrown,
$ ksh Test2.sh
Test2.sh[2]: ^M: not found.
Test2.sh[3]: 0403-057 Syntax error at line 8 : `done' is not expected.

Please give your advice on this.

Regards,
Alo

^M character shows you transfered the script from a windows m/c to unix.

Do this..

Code:

dos2unix Test2.sh

And try to run it now...

If it doesnt work try this

Code:

#! /bin/ksh

while true ;
do
[ -f /synchen/dtazv/fhu/sourcedir ] && echo "/synchen/dtazv/fhu/sourcedir"
#sleep for 1 min
sleep 60
done

Vino

I tried your code on my machine and it works perfect.

Vino