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Find the length of a path

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# 1  
Old 06-11-2012
Find the length of a path
Hey,

I got a question: how do I find the length of a path ?

this is the context:

I used this funtion find:
Code:
DIR="/home/name/directory"
find DIR -name "*.extension"

The output is then:
Code:
/home/name/directory/filename.extension

What I'd like to have is only the last part: filename.extension

I tried with
Code:
find $DIR -name "*.extension" | cut -c${#DIR}-

or even this
Code:
DIR="/home/name/directory"
LENGTH=$(expr length "$DIR")
find $DIR -name "*.extension" | cut -c$LENGTH-

but both gave me a result like this:
Code:
y/filename.extension

Is there any other way to do it or am I doing something wrong ??

Thanks Smilie
Last edited by Scrutinizer; 06-11-2012 at 12:18 PM.. Reason: code tags
# 2  
Old 06-11-2012
Have a look for commands basename and dirname

Assuming you are using ksh script, you can generate the same with:-
Code:
fullpath=/a/b/c/d/file.name

file="${fullpath##*/}"
dir="${fullpath%/*}"

echo $file
echo $dir



I hope that this helps.


Robin
Liverpool/Blackburn
UK
# 3  
Old 06-11-2012
Quote:
Originally Posted by Miki1579
find DIR -name "*.extension"
If you're using GNU find (almost certainly true if you're using Linux) and aren't concerned with other find implementations on other operating systems, you could use:
Code:
find DIR -name '*.extension' -printf '%P\n'

Regards,
Alister
# 4  
Old 06-11-2012
Works great thanks guys !
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