Shell Programming and Scripting

thanks a lot , i'm getting the desired output..

---------- Post updated at 04:04 AM ---------- Previous update was at 03:51 AM ----------

INPUT:1_120606259532_3_4.5_888

if there any many inputs..in all the inputs the date length (bold) is constant ie 12 digits,i need 2 remove the last 4 digits in date field and replace with "9899" and finally the last segment in the file ie 888 needs to be removed.

s t possible??

---------- Post updated at 05:59 AM ---------- Previous update was at 04:04 AM ----------

by assigning some variable as 8899..and then substituting the date field,in the part of the script,is that possible.?

what is the desired output ?

Code:

# echo $INPUT|sed -r 's/(._.{8}).{4}(_.*_).*/\19899\2/'
1_120606259899_3_4.5_

sorry am getting the folllowing error,while executing the above

Code:

sed: Not a recognized flag: r
Usage:  sed [-n] [-u] Script [File ...]
        sed [-n] [-u] [-e Script] ... [-f Script_file] ... [File ...]

u can try this

Code:

# echo $INPUT|sed 's/\(._.\{8\}\).\{4\}\(_.*_\).*/\19899\2/'

thanks a lot its working fine, can you explain that sed command, i am not getting it & more over i want the desired output like 1_120606259899_3_4.5

and second

Code:

# val=9899 ; echo $INPUT|sed 's/\(._.\{8\}\).\{4\}\(_.*_\).*/\1'$val'\2/'

can the command be changed so that the "_" is not coming at the end

---------- Post updated at 07:41 AM ---------- Previous update was at 07:40 AM ----------

current output:1_120606259899_3_4.5_
required:1_120606259899_3_4.5