Shell Programming and Scripting

Hi,
I'm trying to wtite a script which actually print the text which doesn't contain a word , i mean to say.
eg:- if a file contains the follwoing data

Hello how ru ???
What ru doing ?
what is the % of data contained ???

I want to write a script such that it prints the line excluding "%" symbol

If i use grep -v "%" , it prints all lines except the matched pattern i dont want that to be

So you want to replace the '%' with nothing ?

Look at tr or sed, it should be fairly simple.