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Cut line up to a string

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# 1  
Old 05-31-2012
Cut line up to a string
hi all

In my bash script I want to cut a line up to a specific string and keep the rest of it but only up to a ".How can I do that?I imagine something with sed..
Let's say my line is:

Code:
Jennifer Jones (student) "id:376765748587/7465674775" NewYork

and i only want to keep:

Code:
id:376765748587/7465674775

(some lines have more or less words so the number of words is not fixed for a line)
Last edited by Scrutinizer; 05-31-2012 at 07:42 AM.. Reason: code tags
# 2  
Old 05-31-2012
Code:
 echo "Jennifer Jones (student) \"id:376765748587/7465674775\" NewYork"|cut -d"\"" -f2

This User Gave Thanks to donadarsh For This Post:
vlm
# 3  
Old 05-31-2012
Code:
 
echo 'Jennifer Jones (student) "id:376765748587/7465674775" NewYork' | awk -F\" '{print $2}'

This User Gave Thanks to itkamaraj For This Post:
vlm
# 4  
Old 05-31-2012
Code:
echo 'Jennifer Jones (student) "id:376765748587/7465674775" NewYork'|sed 's/.*"\([^"]*\)".*/\1/g'

This User Gave Thanks to elixir_sinari For This Post:
vlm
# 5  
Old 05-31-2012
Code:
while IFS=\" read user id town
do
  echo "$id"
done < file

This User Gave Thanks to Scrutinizer For This Post:
vlm
# 6  
Old 05-31-2012
Quote:
Originally Posted by elixir_sinari
Code:
echo 'Jennifer Jones (student) "id:376765748587/7465674775" NewYork'|sed 's/.*"\([^"]*\)".*/\1/g'

in some lines there're fields with more than one phrace inside "".For example:

Code:
Brad Robins "worker in FGD " LA "id:3476543774/638957685"

so i want to keep only the ones that start with id and finish with a ".
Also in some lines there's more than one field for id.For example:

Code:
Brad Robins "worker in FGD" LA "id:3476543774/638957685" alternative::"id:7567756/38584896"

So is there a way in every line to keep every field that starts with the string 'id' and ends with a "?

The fields for every line might be in different order or column so it's not fixed that in the first column is the name for example,or the id in the 3rd..
# 7  
Old 05-31-2012
Code:
echo 'Brad Robins "worker in FGD" LA "id:3476543774/638957685" alternative::"id:7567756/38584896"'|awk -F\" '{for(i=1;i<=NF;i++) if($i ~ /^id:/) print $i}'

This User Gave Thanks to elixir_sinari For This Post:
vlm
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