Shell Programming and Scripting

Great!Thanks a lot everybody!

---------- Post updated at 08:43 AM ---------- Previous update was at 06:26 AM ----------

I was wondering what if the required field is not inside "" but inside parentheses or brackets?
Then is it something like this?

Code:

echo things | awk -F\(\) '{for(i=1;i<=NF;i++) if($i ~ /^id:/) print $i}'

Because this is not working

Use square brackets to use more than one kind of characters as field separator and do not forget to use quotes around it to protect it from the shell.

-----

you mean something like this:

Code:

awk -F["\(\)"]

because it's not working and I assume there's syntax error

---------- Post updated at 11:45 AM ---------- Previous update was at 09:40 AM ----------

So I tried the following in another case

Code:

if [[ "$line" == *\<img* ]] 
then
  echo found!
  echo $line | awk '{for(i=1;i<=NF;i++) if($i ~ /^img/) print $i}' #| wc -l
fi

now in my file the lines look like this:

Code:

kkk fff hhh<img dddddd <img
kkk fff hhh aaaaaa <img

the command

Code:

echo found!

is executed for both lines ok
but the next echo prints 1 for both lines instead of printing 2 for the
first line and 1 for the second
I assumed the problem is that it doesn't count the <img if before there're letters such as

Code:

dddd<img

although the if statement sees it.So it must be a problem with the awk in that case