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How to convert a file containing hex code to decimal using script?

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Top Forums Shell Programming and Scripting How to convert a file containing hex code to decimal using script?
# 15  
Old 05-31-2012
Try...
Code:
awk 'function p(i){printf "%d.%d.%d.%d ",$i,$(i+1),$(i+2),$(i+3)}{p(5);p(13);p(17);print "c:" $29+$30+$31+$32+$33}' hexdata.log

This User Gave Thanks to Ygor For This Post:
necro98
# 16  
Old 06-01-2012
Thanks very much Ygor , i am getting desired output

Code:
235.20.192.65 10.10.50.9 10.10.39.42 c:0

but this steps need to repeat for each and every line in the file (each line as same number of words 108)
Right now it only checks the first line and gives the output

---------- Post updated 06-01-12 at 12:16 AM ---------- Previous update was 05-31-12 at 11:56 PM ----------

Also need the time stamp to be printed at the beginning of the line

---------- Post updated at 01:49 AM ---------- Previous update was at 12:16 AM ----------

guys , Please can you help out with the above ,

I really appreciate the efforts taken by all your efforts so far
Last edited by Scrutinizer; 06-01-2012 at 01:59 AM.. Reason: code tags
# 17  
Old 06-01-2012
Not sure what you mean by a time stamp?

Anyway, combining the awk code above gives you something to try...
Code:
$ cat hex.txt
00 00 00 04 0A 02 05 01 00 00 00 00 0A 0A 32 C7 00 00 00 00 0A 0A 32 F3 0A 0A 2B 2D 00 00 00 00 00 00 00 08 80 01 06 6D 26 E4 00 02 00 00 00 00
06 6D 0A 80 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00

$ cat prog.awk
        function p(i)
        {
                printf "%d.%d.%d.%d ", $(i), $(i + 1), $(i + 2), $(i + 3)
        }

        {
                for (i = 1; i <= NF; i++) {
                        $i = sprintf("%0d", "0x" $i)
                }
                printf "%s ", ts
                p(5)
                p(13)
                p(17)
                print "c:" ($29 + $30 + $31 + $32 + $33)
        }

$ gawk --posix -f prog.awk ts=$(date '+%Y%m%d%H%M%S') hex.txt > result.txt

$ cat result.txt
20120601110632 10.2.5.1 10.10.50.199 0.0.0.0 c:0
20120601110632 0.0.0.0 0.0.0.0 0.0.0.0 c:0

$

# 18  
Old 06-02-2012
Thanks ygor , by timestamp i meant the current time , i tried the steps you mentioned but it gives all zeroes

Code:
-bash-3.2$ gawk --posix -f prog.awk ts=$(date '+%Y%m%d%H%M%S') Hex.txt
20120602173822 0.0.0.0 0.0.0.0 0.0.0.0 c:0
20120602173822 0.0.0.0 0.0.0.0 0.0.0.0 c:0
20120602173822 0.0.0.0 0.0.0.0 0.0.0.0 c:0

Last edited by Scrutinizer; 06-02-2012 at 05:41 AM.. Reason: code tags
# 19  
Old 06-03-2012
try option --non-decimal-data
# 20  
Old 06-03-2012
Ygor ,How do i user that option ?where do i set it
# 21  
Old 06-04-2012
I suspect you want to break input up into 108 byte records.

Try this slight change to Ygor's program:

Code:
$ cat prog.awk
  function p(i)
  { 
      printf "%d.%d.%d.%d ",P[i],P[i+1],P[i+2],P[i+3]
  }
  {
     for(i=1;i<=NF;i++) {
        P[++N]=sprintf("%0d", "0x"$i);
        if(N>107) {
           N=0;
           printf "%s ", ts;
           p(5)
           p(13)
           p(17)
           print "c:" P[29]+P[30]+P[31]+P[32]+P[33]
        }
     }
   }
$ gawk --non-decimal-data -f prog.awk -vts=$(date '+%Y%m%d%H%M%S') hex.txt > result
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