yesterday's "weekday" date


 
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# 1  
Old 05-29-2012
yesterday's "weekday" date

i've been going through https://www.unix.com/answers-frequent...rithmetic.html to find a cmd that will print me yesterday's date. I have found one that does it nicely


Code:
set YEST = `date '+20%y/%m/%d' | awk -F"/" '{print $1$2($3-1)}'`

as you can see its very rudimentary i.e is subtracting 1 from the day.
im looking to make this a little clever and take into account weekend such that if executed on a monday, it would return Friday's date.
# 2  
Old 05-29-2012
Hi
If you have -d option in your date command:


Code:
$ date -d "yesterday" '+20%y/%m/%d'
2012/05/28


Guru.
# 3  
Old 05-29-2012
That regular date with awk in post #1 will not work correctly on the first day of the month...

---
ksh93h+:
Code:
printf "%(%Y/%m/%d)T\n" yesterday


Last edited by Scrutinizer; 05-29-2012 at 01:07 PM..
This User Gave Thanks to Scrutinizer For This Post:
# 4  
Old 05-29-2012
Quote:
Originally Posted by Scrutinizer
That will not work correctly on the first day of the month...

---
ksh93h+:
Code:
printf "%(%Y/%m/%d)T\n" yesterday

is yesterday a shell variable? I'm scripting in ksh and executing under bash
UPDATE: ignore, i see this is ksh

Last edited by jack.bauer; 05-29-2012 at 12:24 PM.. Reason: ignore, see this is ksh
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