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sed to remove braces from a file

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# 1  
Old 05-28-2012
sed to remove braces from a file
i need to search for user belonging to group 'macusr' and the extract the user name .
i am able to write a oneliner for this using awk + sed + tr

i am using tr to chop off '()' from the output. but i want to use it in sed itself . can someone please help me with that

file contents

Code:
uid=1700(john) gid=1700(john) groups=4500(dba),1604(users),61343(macusr)
uid=1456(ben) gid=1456(ben) groups=11001(cap)



Code:
cat myfile | awk '/macusr/{print $1}' | sed 's/^uid=[0-9]*//g' | tr -d '()'

i want to remove that tr part and want to achieve its functionality in sed part itself. Please help me.
# 2  
Old 05-28-2012
Try

Code:
sed -n '/^uid=[0-9]*(\([^)]*\)).*groups=.*(macusr).*/s||\1|p' <filename>

By the way, that's a useless use of cat...awk can handle filenames as arguments.
# 3  
Old 05-28-2012
Hi

Code:
awk -F '[=)(]' '/macusr/{print $3}' file

OR

Code:
sed -n '/macusr/s/uid=[0-9]*(\([a-z]*\).*/\1/p' file

Guru.
Last edited by guruprasadpr; 05-28-2012 at 09:00 AM.. Reason: adding sed option
# 4  
Old 05-28-2012
Thanks. both codes are working.. but can you please explain me the sed oneliner

---------- Post updated at 07:08 AM ---------- Previous update was at 07:03 AM ----------

also i have i have id with pattern like ml345 instead of user like john

i.e.

uid=1700(ml345) gid=1700(ml345) groups=4500(dba),1604(users),61343(macusr)

now the above one liner didnt work on this patten.. please help me with one liner for this pattern
# 5  
Old 05-28-2012
Did you try mine with that input? It will work.

---------- Post updated at 07:26 AM ---------- Previous update was at 07:20 AM ----------

Code:
/^uid=[0-9]*(\([^)]*\)).*groups=.*(macusr).*/

is used to select those lines that contain the "macusr" group. In this expression, the username is "marked" with a tagged regular expression using \( and \). In these selected lines, I am substituting the remembered pattern (||, that's the pattern searched for(the entire line)) with \1. \1 indicates the first "tagged" pattern which in this case is the username.
This User Gave Thanks to elixir_sinari For This Post:
chidori
# 6  
Old 05-28-2012
yes.. Thanks your code works fine.. i am still trying to understand it Smilie

Code:
/^uid=[0-9]*(\([^)]*\)).*groups=.*(macusr).*/

does that highlighted part refer to (user_name) ?? like in my case (john) , (ben) , (ml345) ?
# 7  
Old 05-28-2012
Quote:
Originally Posted by chidori
yes.. Thanks your code works fine.. i am still trying to understand it Smilie

Code:
/^uid=[0-9]*(\([^)]*\)).*groups=.*(macusr).*/

does that highlighted part refer to (user_name) ?? like in my case (john) , (ben) , (ml345) ?
Yes, I am marking the pattern within the parentheses (the ones without the escape slashes) with the TRE. 0 or more occurrences of a character which is not the closing parenthesis [)] will give only the pattern with the parentheses. This is important as a pattern such as .* would have matched any character including the closing ) [which we don't want].
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