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awk read RS

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# 1  
Old 05-23-2012
awk read RS
I need to know if there is a way to use the while read command from a awk record. The record has 3 or 4 lines and I need the line to be all of the record instead of just each line of it.
Code:
nawk 'BEGIN {RS="!"} /atm pvc/ {print $0}' router.list | while read line
do
VP=`echo "$line" | egrep "atm pvc" | nawk '{print $4}'`
VC=`echo "$line" | egrep "atm pvc" | nawk '{print $5}'`
PROFILE=`echo "$line" | egrep "atm pvc" | nawk '{print $7}'`
ENACP=`echo "$line" | egrep "encapsulation"`
INTERFACE=`echo "$line" | egrep "ip description" | nawk '{print $3}'`
echo "atm pvc $VP $VC profile dsl-$PROFILE $ENCAP"
if [[ $ENCAP == "encapsulation pppoe" ]] ; then
echo "bind authentication pap maximum 1"
else
echo "bind interface $INTERFACE [ADSL]"
fi
done

An example of the input file is:
Code:
interface atm 1/0.20292 point-to-point
 atm pvc 100020292 2 292 aal5snap 768 768 10
 encapsulation pppoe
! 
interface atm 1/0.20292.1
 encapsulation ppp
 ppp authentication pap
 profile any "prof-pppoe"
! 
interface atm 1/0.20293 point-to-point
 atm pvc 100020293 2 293 aal5snap 1500 1500 10
 encapsulation pppoe
! 
interface atm 1/0.20293.1
 encapsulation ppp
 ppp authentication pap
 profile any "prof-pppoe"
! 
interface atm 1/0.20294 point-to-point
 atm pvc 100020294 2 294 aal5snap 1500 1500 10
 encapsulation pppoe
! 
interface atm 1/0.20294.1
 encapsulation ppp
 ppp authentication pap
 profile any "prof-pppoe"
! 
interface atm 1/0.20295 point-to-point
 atm pvc 100020295 2 295 aal5snap 3000 3000 10
 encapsulation pppoe
! 
interface atm 1/0.20295.1
 encapsulation ppp
 ppp authentication pap
 profile any "prof-pppoe"
! 
interface atm 1/0.20296 point-to-point
 atm pvc 100020296 2 296 aal5snap 6000 6000 10
 encapsulation pppoe
! 
interface atm 1/0.20296.1
 encapsulation ppp
 ppp authentication pap
 profile any "prof-pppoe"
! 
interface atm 1/0.20297 point-to-point
 atm pvc 100020297 2 297 aal5snap 1500 1500 10
 encapsulation pppoe
! 
interface atm 1/0.20297.1
 encapsulation ppp
 ppp authentication pap
 profile any "prof-pppoe"
! 
interface atm 1/0.20298 point-to-point
 atm pvc 100020298 2 298 aal5snap 3000 2900 10
 encapsulation bridge1483
 ip description AAAService-1/0-2-298 [local]
 ip address 192.168.217.86 255.255.255.248
!

# 2  
Old 05-23-2012
And the expected output is ... ?
# 3  
Old 05-23-2012
For an example, of one record.
Input
Code:
interface atm 1/0.20293 point-to-point
 atm pvc 100020293 2 293 aal5snap 1500 1500 10
 encapsulation pppoe

Output
Code:
atm pvc 2 293 profile dsl-1500 encapsulation pppoe
bind authentication pap maximum 1

# 4  
Old 05-23-2012
And... What logic converts one to the other? Where does 'dsl-' come from? etc.
# 5  
Old 05-23-2012
Code:
awk '/^!/ && prf { 
    print atm, atm_, vp, vc, prf, encap
    print "bind", (encap == "pppoe" ? "authentication pap maximum 1" : iface)
    prf = encap = x    
  }
/atm pvc/ { 
  atm = $1; atm_ = $2; vp = $4; 
  vc = $5; prf = "profile dsl-" $7 
  }
/encapsulation/ { encap = $2 }
/ip description/ { iface =  "interface " $3 " [ADSL]" }
  ' infile

Last edited by radoulov; 05-23-2012 at 07:32 PM.. Reason: Shortened ...
# 6  
Old 05-23-2012
from an echo statement with variables pulled from the awk record like:
Code:
echo "atm pvc $VP $VC profile dsl-$PROFILE $ENCAP"

---------- Post updated at 05:32 PM ---------- Previous update was at 05:25 PM ----------

Radoulov, I get the folling from your code:
Code:
#
awk: syntax error near line 3
awk: illegal statement near line 3
awk: syntax error near line 5
awk: bailing out near line 5
 
#!/bin/ksh 
#
awk 'END {
  if (prf) print atm, atm_, vp, vc, prf, encap
  print "bind", (encap == "pppoe" ? "authentication pap maximum 1" : iface)
  }
/^interface/ {
  if (prf) {
    print atm, atm_, vp, vc, prf, encap
      print "bind", (encap == "pppoe" ? "authentication pap maximum 1" : iface)
    prf = encap = iface = x
    }
  }
/atm pvc/ {
  atm = $1; atm_ = $2; vp = $4;
  vc = $5; prf = "profile dsl-" $7
  }
/encapsulation/ { encap = $2 }
/ip description/ { iface =  "interface " $3 " [ADSL]" }
  ' input.file

# 7  
Old 05-23-2012
Quote:
Originally Posted by numele
Radoulov, I get the folling from your code:
Code:
#
awk: syntax error near line 3
awk: illegal statement near line 3
awk: syntax error near line 5
awk: bailing out near line 5
[...]

Try the new version and use nawk instead of awk.
This User Gave Thanks to radoulov For This Post:
numele
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