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Cron for end of month

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# 8  
Old 06-02-2012
I would have done it this way:

Code:
if awk -v date="$(date "+%Y %m %d" )" '
    BEGIN {
        split( date, dt, " " );
        split( "1 -2 1 0 1 0 1 1 0 1 0 1", dim, " " );                                  # days in month; sort of
        dim[2] += dt[1]%4 != 0 ? 0 : (dt[1]%100 != 0 ? 1 : (dt[1]%400 != 0 ? 0 : 1));   # adjust for leap year

        exit( !( dt[3] == dim[dt[2]] + 30) );       #true if last day, invert because for shell, exit code 0 is success 
    }
'
then
    echo "last day"    # put your logic to remove files here
else
    echo "not last day"
fi



You can test (regardless of day) by replacing the initial if expression with something like the line below which has the date hard coded:

Code:
if awk -v date="2012 06 30" '

This User Gave Thanks to agama For This Post:
user`
# 9  
Old 06-03-2012
Quote:
Originally Posted by user`
Hi, just wanted to give updates regarding the end of month script. I tried Chubler_XL codes and unfortunately it didn't work. I was waiting for 05/31.

This is what i have tried:

Code:
59 23 * * * /home/user/eomt.sh >/dev/null 2>&1

eomt.sh:

Code:
#!/bin/sh
 
if [ `date +%d` -eq `awk '$NF{E=$NF} END{printf E}'` ]
then
    rm /home/user/tst/logs/* && rm /home/user/tst/stats/*
fi
exit 0

I also tried to run the script manually by using ./eomt.sh and it doesn't even come out.

best regards
user
Oops something seems to be missing here try:

Code:
#!/bin/sh
 
if [ `date +%d` -eq `cal | awk '$NF{E=$NF} END{printf E}'` ]
then
    rm /home/user/tst/logs/* && rm /home/user/tst/stats/*
fi
exit 0

These 2 Users Gave Thanks to Chubler_XL For This Post:
agama user`
# 10  
Old 06-04-2012
agama, Chubler_XL , thanks so much. I'll try this.
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