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sed to replace the matching pattern with equal number of spaces

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# 1  
Old 05-16-2012
sed to replace the matching pattern with equal number of spaces
Hi

I have written a shell script which used sed code below

Code:
sed -i 's/'"$Pattern"'/  /g' $FileName

I want to count the length of Pattern and replace it with equal number of spaces in the FileName.

I have used $(#pattern) to get the length but could not understand how to replace with equal spaces.

Any help is much appreciated
# 2  
Old 05-16-2012
Hi rakeshkumar,

Using perl:
Code:
$ perl -i -pe 's/(pattern)/q[ ] x length $1/ge' infile

# 3  
Old 05-16-2012
With awk:
Code:
awk -v p="$Pattern" 'BEGIN{l=length(p);s=sprintf("%"l"s","")} $0 ~ p{sub(p,s)}1' file > newfile

# 4  
Old 10-24-2012
Hi ,
I have a doubt here
If my pattern is not fixed , like in below case then how can I do that using sed command .
I tried using awk command but it replaced N with Y in entire file.txt

Code:
 
awk -F '=' '{if ($1 == "test") {print $1"=Y"} else {print $1"=N"}}'  file.txt

input
Quote:
test_F1=N
test_F2=N
test1_F1=N
test2_F3=N
output
Quote:
test_F1=Y
test_F2=Y
test1_F1=N
test2_F3=N
Regards,
Haris
# 5  
Old 10-24-2012
I don't understand your question, not to mention how it might be related to this long-dormant thread.

Regards,
Alister
# 6  
Old 10-24-2012
How do i Replace if the pattern what I am trying to search is not fixed , like in the previous post as i have mentioned

I have to replace all flag values "N" to "Y" only for string starting with test and not for test1

Regards,
Harish
# 7  
Old 10-24-2012
Code:
sed -n '/test_/ s/N$/Y/;p' input_file
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