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Simple loop using for

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# 1  
Old 05-13-2012
Simple loop using for
Dear experts,

I am writing a bash script. At some point of the program I need to have 'for' loop. For simplicity I tried with some other simple code. The format of the loop is given below.

Code:
k=51 
m=55

for j in {$k..$m};do
	w=$(($j+2))
	z=$(($j+9))

echo "$w, $z" 

done

But my code is fail to run.

Basically I want the k and m to variable.

Can anyone address some point here?
Appreciate any help in advance.

Thanks
# 2  
Old 05-13-2012
Try:
Code:
for (( j=$k; j<=$m; j++ )); do

This User Gave Thanks to Scrutinizer For This Post:
vjramana
# 3  
Old 05-13-2012
No need to use $ in for (( ...)) operations
Code:
for ((j=k; j<=m; j++))
do
   w=$((j+2))
   z=$((j+9))
   echo "$w, $z"
done

# 4  
Old 05-13-2012
Thanks.
It works well now.

Regards
# 5  
Old 05-13-2012
or a not so reliable way
Code:
k=51 
m=55
for j in $(eval echo {$k..$m});do
    echo $((w=j+2)) $((z=j+9))
done

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