This is a very interesting problem. Perhaps the best (=simpliest) solution is the one from Scrutinizer and it is quite idle musing to try something in one tool (sed) which could be done a lot easier in another. Still, just to satisfy my curiosity:
Several posters here have suggested variants of the following algorithm: replace every three characters with these characters plus an appended comma. Reverse before and after this:
This may work but it is interesting to try to solve it in sed alone. It is possible to set up a loop appending the rightmost character to holdspace until the pattern space is empty. This would effectively do the same as the rev utility.
But there is a much simplier way to achieve our goal. Let us first apply our algorithm without using the rev utility. The outcome, depending on the length of the number, would be one of the following three forms:
We can correct the first one by moving all the commata 2 places leftwards. The second variant can be corrected by moving the commata 1 place leftwards and the last line just has one superfluous comma in the end. Therefore:
Which will do the trick in sed alone. My curiosity is satisfied indeed.
bakunin
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Hello,
I have a log file with logs such as
01/05/2017 10:23:41 : file.log.38: database error, MODE=SINGLE, LEVEL=critical, STATE: 01170255 (mode main
how can i use perl to extract the 8-digit number below from the string
01170255
Thanks (7 Replies)
hello
i have file with 100k records and each one has certain value that starts at 28th column and certain value that starts at 88th column
e.g. 1st file
<25>1234567 ..... <88> 8573785485
i have aditional file with values which are related to value that starts at 88th column of the... (1 Reply)
Hi Guys,
I want to search for a specific file in a directory which have a "b" letter as the 3rd character in the name of the file.
For Example :
/abc/efg/ldbjfblkj.sh
/abc/efg/erublkd.sh
/abc/efg/eibueora.sh
/abc/efg/kfvnmnb.sh
Since we have 2 files with "b" as a 3rd character in... (5 Replies)
I have a awk file which consists of the follwoing code in file select.awk :
/xxx/ {
time = gensub(/xxx \*\*\*(.*)/, "\\1", "g")
printf("%s\n",time)
next
}
and an input file with the following file file.txt :-
xxx ***Wed May 2 18:00:00 CDT 2012
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I would like to search between two a string. I thought this would be easy. The is always at the beginning of a line.
The code:
gawk '/^/{d=$1},/searchstring/,/^(d+1)/'
or
gawk '/^/,/searchstring/,/^/'
did not return the desired result.
inputfile.txt
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Hi Experts,
I have called some.txt with the following content.
oracle HYRDSRVIHUB01 pts/0 TESTIHUB 07-JUN-10 CREATE TABLE
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Hi guys,
I am not very experienced in writing ksh scripts and I am trying to write a piece of code that indicates if a given string contains only digits and no alphabet (upper or lower case). If i write it my way it would turn out to have a lot of comparisons.. :eek:
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Hi,
I remember once seeing a way to get the left most string in a word.
Let's say: a="First.Second.Third" (separated by dot)
echo ${a#*.} shows --> Second.Third
echo ${a##*.} shows --> Third
How do I get the the left most string "First" Or "First.Second" ???
Tried to replace #... (2 Replies)