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How can we get the character before and after a word in a string?

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Top Forums Shell Programming and Scripting How can we get the character before and after a word in a string?
# 1  
Old 05-07-2012
How can we get the character before and after a word in a string?
Hi friends,
I am working in a korn shell. i want to know the command which gives me the previous one character and next one character of a given keyword in a string?

for exmaple:
input string:
Code:
/bin/dir/folder1/.proc_name^folderone

Keyword:
Code:
proc_name

output :
Code:
.^

Thanks in advance Smilie
Last edited by Scrutinizer; 05-12-2012 at 07:50 AM.. Reason: code tags
# 2  
Old 05-07-2012
Can try:
Code:
$ var='/bin/dir/folder1/.proc_name^folderone'
$ echo "$var" | sed 's/.*\(.\)proc_name\(.\).*/\1\2/'
.^

You can try something like this with parameter expansion if your ksh is modern:

Code:
$ var='/bin/dir/folder1/.proc_name^folderone'
$ str=proc_name
$ i=${var%?"$str"*}
$ echo ${var:${#i}:1}${var:${#i}+${#str}+1:1}
.^

# 3  
Old 05-12-2012
@neutronscot: thansk for your solution.
but the 1st method :
Code:
$ var='/bin/dir/folder1/.proc_name^folderone'
$ echo "$var" | sed 's/.*\(.\)proc_name\(.\).*/\1\2/'
.^

above method works fine if there is atleast one chanracter before the "proc_name" and after the "proc_name" BUT it is not woking fine if there is no character before the procname or/and after the rpocname.
for example:
Code:
 echo "bin/dir/folder1/.proc_name^folderon" | sed 's/.*\(.\)proc_name\(.\).*/\1\2/'

output:
Code:
.^

working fine in above case.

BUT

Code:
echo "proc_name^folderon" | sed 's/.*\(.\)proc_name\(.\).*/\1\2/'

output:
Code:
proc_name^folderon

NOT WORKINg FINE IN THE ABOVE CASE Smilie

anyone please help!!!!

Moderator's Comments:
Mod Comment Please view this link: How to use [code]...[/code] tags
Last edited by Scrutinizer; 05-12-2012 at 07:49 AM..
# 4  
Old 05-12-2012
It is working fine, also in that case, since you did not specify this in your requirements. What output are you looking for in that case, and also when the keyword is at the end?
# 5  
Old 05-12-2012
@Scrutinizer I am not telling that he is wrong. he gave me the solution what i asked.
But now i am facing this issue . and and if the keyword is at the end also , i am not getting the result
# 6  
Old 05-12-2012
Yes, because you did not specify this case. So what are you looking for? Only 1 character in that case?
# 7  
Old 05-12-2012
yes only one character in this case .. two in my previous case and if there are no character before and after the keyword i.e if the var and keyword are same, i want to get null .. Smilie
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