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grep ip address from file

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# 1  
Old 05-07-2012
grep ip address from file
I have a file

Code:
[me@server hi]$ cat ip12
11.22.33.44
192.68.1.2
helo
l
72.34.34.200
333.444.555.666
12.23e.544.423
myip1 11.22.33.44
myip2 33.44.55.66 #fine this IP should also be listed

I do
Code:
[me@server hi]$ cat  ip12 | grep '^[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}$'
11.22.33.44
192.68.1.2
72.34.34.200
333.444.555.666

I get results of IP address, but I need here 11.22.33.44 ad 33.44.55.66 also listed.

---------- Post updated at 03:18 AM ---------- Previous update was at 03:15 AM ----------

Nevermind I got it

Code:
[me@server me]$ cat  ip12 | grep -E -o '(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)'
11.22.33.44
192.68.1.2
72.34.34.200
11.22.33.44
33.44.55.66

# 2  
Old 05-07-2012
The below regex is for identify the valid ip address.

Regular Expression Examples

Code:
 
\b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b

# 3  
Old 05-10-2012
From your first command:
Code:
cat  ip12 | grep '^[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}$'

just remove ^ and $ symbols:

Code:
 #cat  ip12 | grep '[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}'
11.22.33.44
192.68.1.2
72.34.34.200
333.444.555.666
myip1 11.22.33.44
myip2 33.44.55.66 #fine this IP should also be listed

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