Shell Programming and Scripting

Hi I am totally new to Unix and I am in need of a script that can grep several files at once.
the script needed:
change directory
grep for keywords "error" "fail" "warning" in different files with different names, same extention but specific file names.
if any of the keywords is found to show the line number and the error

I usually run this grep manually every hour and it's time consuming, running a cron is not an option, so I would just copy and paste the script when needed.

Any help will be greatly appreciated.

Thanks,

Newby in need.

use -n option for grep.

Code:

grep -en "error|fail" *

Hi Bhargav,

Is there any way to grep a keyword in all files - including those in the subdirectories as well. I usually use this method of coding:

for j in `find ./*`
do
grep <keyword> $j
done

But just out of curiosity - is there any other methods to perform the same.. which looks much simpler (instead of taking such multiple lines!!)

find /path/here -type f -exec grep "whatever" {} /dev/null \;

Cheers
ZB

You can use find + xargs + grep to do this by one command as,

find <dir to be grepped> -name "*" | xargs grep -ne 'error|fail|warning'

It will do it.