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awk transpose row into 2 field column

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# 8  
Old 05-03-2012
Quote:
Originally Posted by Corona688
Code:
awk '{ D[++L]=$0 }
(!MAX) || (NF>MAX) { MAX=NF }

END {
        for(M=1; M<=MAX; M+=2)
        for(N=1; N<=L; N++)
        {
                $0=D[N];
                print $M, $(M+1);
        }
}' datafile

Yes the sorting works, though when the input has different number of columns, the script writes for each missing column a blank line. Isn't the asort function more concise?

input:
HTML Code:
 1 450 129 70 229 130 296 160
 5 65 131 675 230 75
 6 55 132 45
 11 48
output:
HTML Code:
1 450
5 65
6 55
11 48
129 70
131 675
132 45
 
229 130
230 75
 
 
296 160
# 9  
Old 05-03-2012
awk transpose row into 2 field column
Hi Combo,

Thanks for this, still I need to understand this logic:

1. First you are putting every row in array
Code:
D

start with
Code:
D[1]

2. Then you are setting variable MAX. Are you checking this for every line. What is the value of
Code:
MAX

.

3.
Code:
END

section will execute finally when everthing is done right. Please explain.

Code:
awk '{ D[++L]=$0 }
(!MAX) || (NF>MAX) { MAX=NF }
END {
        for(M=1; M<=MAX; M+=2)
        for(N=1; N<=L; N++)
        {
                $0=D[N];
                print $M, $(M+1);
        }
}' datafile
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