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How to cut string and find missing pattern?

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# 8  
Old 05-01-2012
If AWK it was working that way, END section would be useless. Now you didn't answer my question: did you try my code?
# 9  
Old 05-01-2012
dear bartus11 ,

i have tried urs suggested solution ....after giving the command its giving the output list from 01 to 24 but missing pattern is from 13 to 24


the command i am giving is mentioned in above post

thanks for reply.
# 10  
Old 05-01-2012
What operating system are you using?
# 11  
Old 05-01-2012
dear all,

i have opened my file in vi editor

its showing my file string as

Code:
^[[00mqm12010512.^[[00m^M


but after opening with cat its showing
Code:
qm12010512.

will it create any problem in execution of command suggested above

if its so plz suggest something.
# 12  
Old 05-01-2012
Yes, it means that you have Windows line ending characters there. Run
Code:
dos2unix filename

before running the AWK code.
# 13  
Old 05-01-2012
My O/S is HP unix and shell is sbin/sh

and i have tried this command its showing the following error
Code:
dos2unix file.txt
sh: dos2unix:  not found.

i have to do this with script
hence plz suggest in that way

thanks for quick reply
# 14  
Old 05-01-2012
remove those characters by using the below command.

Code:
perl -pe 's/\033\[[^m]*m//g' < input.txt > output.txt

now open the output.txt and see, whether those weired characters are there or not

---------- Post updated at 05:23 PM ---------- Previous update was at 05:22 PM ----------

After that, try the below

Code:
$ for i in {01..24}; do grep "^qm$i" output.txt > /dev/null 2>&1 || echo "qm"$i"21412"; done

This User Gave Thanks to itkamaraj For This Post:
sagar_1986
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