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Divide data with specific column values into separate files

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# 1  
Old 04-24-2012
Divide data with specific column values into separate files
hello!
i need a little help from you Smilie ... i need to split a file into separate files depending on two conditions using scripting. The file has no delimiters. The conditions are col 17 = "P" and col 81 = "*", this will go to one output file; col 17 = "R" and col 81 = " ". Here is an example.

Code:
132855300       PASSOCIATED ASSOCIATEDL091000022160233784638     075911600000003*0D
140422500       PCHAD NOBASIC PT LTD   0759179119201017796       075911600000004*0D
144243100       RWASHINGTON CARDWELT SC0759061710110013401       075911600000001 17
40402357604     RMD ADVICE       95148R27507971438278102         075000020000002*0D
48412698886     RTHOMAS KLOEH  1918883R07591176887066770         075000020000003 0D
41406992615     RSAMIHA KADAD 26174726Y07500001900000000044697352075000020000001 13

Thanks in advance for your help,

Moderator's Comments:
Mod Comment Please use next time
code tags for your code and data
Last edited by vbe; 04-24-2012 at 03:15 PM..
# 2  
Old 04-24-2012
Hi, try this:
Code:
awk '{a=substr($0,17,1); b=substr($0,81,1)} a=="P" && b=="*"{print > "outfile1"} a=="R" && b==" "{print > "outfile2"}' infile

or:

Code:
awk 'sub(/^.{16}P.{63}\*/,"&"){print > "outfile1371a"} sub(/^.{16}R.{63} /,"&"){print > "outfile1371b"}' infile

( if your awk is GNU awk it needs to be called as awk --posix )



Or perhaps your awk can do this:
Code:
awk '$17=="P" && $81=="*"{print > "outfile1"} $17=="R" && $81==" "{print > "outfile2"}' FS= infile

Last edited by Scrutinizer; 04-24-2012 at 05:02 PM..
This User Gave Thanks to Scrutinizer For This Post:
chanclitas
# 3  
Old 04-24-2012
thanks a lot! it works great Smilie
i just have a quick question ... how can i extract only the first record into a new file? Smilie
# 4  
Old 04-24-2012
You could prepend:
Code:
FNR>1{exit}

This User Gave Thanks to Scrutinizer For This Post:
chanclitas
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