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getting part of directory after a certain /

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# 1  
Old 04-22-2012
getting part of directory after a certain /
i have a directory like this:

i want to get the subpaths:
/home/user/public_html/a/b
subpath= a/b

/home/user/public_html/a/b/c
subpath= a/b/c


i can get the user like
Code:
echo $fulldirectory |awk -F/ '{print $3}'

but im not sure how to get the rest of it after public_html

any ideas?
thanks!
Moderator's Comments:
Mod Comment Link: How to use code tags
Last edited by Scrutinizer; 04-22-2012 at 03:00 AM..
# 2  
Old 04-22-2012
Code:
echo $fulldirectory | cut -d / -f 4-

This User Gave Thanks to Skaperen For This Post:
vanessafan99
# 3  
Old 04-22-2012
Code:
echo "${fulldirectory#/*/*/*/}"

This User Gave Thanks to Scrutinizer For This Post:
vanessafan99
# 4  
Old 04-22-2012
thanks for answering Smilie
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