Shell Programming and Scripting

Hi Corona, really i want some like:

Code:

awk -v start="$(date -d '1 mins ago' + '%b %d %T') -v end="$(date +'%b %d %T')" '{tm=$1" "$2" "$3}; start<tm&&tm<end' /path/to/log.log

but, i need it, for a output like before show:

Code:

xxxx 16/04/2012 17:00:53 - xxxx751 - A234 - Time=        61 ms.

---------- Post updated at 06:38 PM ---------- Previous update was at 02:25 PM ----------

maybe im not expressing better way, the parse will extract from the log the complete log generated in the las minute example:

Code:

$date
$Fri Apr 20 18:09:00 GRNLNDST 2012

So the awk will take the values between the 18:08:00 to 18:09:00,

It's asigned to cron, and for this reason the script here just will take the complete log at the minute them put the output on file.


greetings

If you can arrange the dates in YYYY MM DD HH MM SS order, they will sort alphabetically. So it's a matter of reordering:

Code:

awk -v start="$(date -d '1 mins ago' +'%Y %m %d %H:%M:%S') -v end="$(date +'%Y %m %d %H:%M:%S')" '{split($1, D, "/"); tm=D[3]" "D[2]" "D[1] " " $2}; start<tm&&tm<end' /path/to/log.log