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Count occurences based on interval


 
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# 1  
Old 04-19-2012
Count occurences based on interval

Hi,

I have a file which has 4500 entries

Code:
10000
9880
9800
8700
8200
...
.....
...
...
...
...
...
...
...
50

What I need is for every one percentile count number of rows falling into that interval

output
Code:
10000-9900  1
9899-9800  2
9799-9700  0
so on...

Thanks,

Last edited by Diya123; 04-19-2012 at 02:45 PM..
# 2  
Old 04-19-2012
Quick and dirty ..
Assuming ur input is in a file called t1
Paste the below in a file
Code:
#!/bin/ksh
sort -n t1|grep . > t2.tmp
maxval=`tail -1 t2.tmp`
count=0
endv=$maxval
let startv=$maxval/100
let startv=$startv*100
let endv=$startv+99
while test $endv -ge 99
do
cat t2.tmp|while read line
do
if test $line -ge $startv && test $line -le endv
   then
   let count=$count+1
fi
done
echo "${startv}"-"${endv}" "$count" >> Summary.txt
count=0
let startv=$startv-100
let endv=$endv-100
done

The output should be in Summary.txt

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