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grep a string in a file

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# 8  
Old 04-13-2012
Output like this?
Code:
ram
shyam

Try
Code:
awk '{print $(NF-2)}' RS="comp" FS="\n" test

(although I imagine it will produce odd output if 'comp' isn't the only thing on the line)
# 9  
Old 04-13-2012
Thanks for the reply.
It's giving me o/p like below with a blank line under "omp".data is same as i mentioned in the file.txt.

ram
shyam
omp
# 10  
Old 04-13-2012
See if this works:
Code:
awk '{ A[NR%(n+1)]=$0 }; $0~s {i=(NR-n)%(n+1); if (i in A) print A[i] }' s=comp n=4 infile


@CarloM, in standard awk RS needs to be a single character, or rather the first character of a string is used. Only mawk and gawk have an extension so that RS can be a regular expression..
This User Gave Thanks to Scrutinizer For This Post:
CarloM
# 11  
Old 04-16-2012
Please help me in this as i'm not getting how to get the each occurrence of a string which is 26 lines above of another string in a file.
# 12  
Old 04-16-2012
Use n=26 instead of n=4




--
On Solaris use /usr/xpg4/bin/awk instead of awk
This User Gave Thanks to Scrutinizer For This Post:
p.bhaskar
# 13  
Old 04-16-2012
Hi,

I have run the code provided by you but it's giving me below o/p.

Code:
cat data.log
ram
dept
comp
shyam
field
comp

Code:
awk '{ A[NR%(n+1)]=$0 }; $0~s {i=(NR-n)%(n+1); if (i in A) print A[i] }' s=comp n=4 data.log>
dept

It is printing "dept" string.But in data.log i need to print "ram" and "shyam" string.
Moderator's Comments:
Mod Comment How to use code tags
Last edited by Scrutinizer; 04-16-2012 at 03:39 AM..
# 14  
Old 04-16-2012
Then use n=2
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p.bhaskar
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