Shell Programming and Scripting

Hi, I have some backup scripts running.
They allocate the files in separated folders, according to the current day.
(01, 02, 03...., 31)
After 1 month, the "cycle" starts again, and the files are uploaded to the folder 01, 02...
When that happens, I want the previous files to be deleted, so that I can put the new ones.

The backup script looks something like this:

Code:

#!/bin/bash
FILE="ccih-`date +%Y-%m-%d_%Hh%Mmin`"
DAY="`date +%d`"
MONTH="`date +%m`"

ftp -ni $FTPSERVER <<FIM
user $USERNAME $PASSWORD
lcd $LOCALDIR
cd $DAY
binary
mput $FILE.tar.bz2
bye
quit
FIM

I want to use mdelete to delete the older files, so it would look something like

Code:

mdelete ccih-2012-<??? WILDCARD THAT INDICATE DIFFERENT FROM THIS MONTH???>-*min.tar.bz2

I would appreciate your help.. I've tried every kind of regex...
Thanks in advance...

Why not just upload after deleting, instead of deleting everything except the one just uploaded?

Further to Corona688's excellent post.
If you have three separate runs of ftp (directory run; delete run; transfer run) you can first find out which files (if any) are present in the target directory, then delete them in a controlled manner if required, then transfer the new files.

Btw. In the script posted your mput will only transfer one file (if it exists ... which is unlikely).

Hi!
Corona688, methyl
This script transfers only one file each time it runs, the problem is that it runs several times a day.
It would be a perfect solution to delete everything on the folder before uploading, but I don't want to delete everything, I just want to delete files that were created "last" month.
Supposing it is the third time today that the script runs, it would delete the first and second copies I've done today, while I just wanted to delete copies from previous months.

I was thinking about using a wildcard that indicates difference, but I've tried several methods and it didn't work... Looks like only the wildcard "*" is permitted in this case (correct me if I'm wrong).

I've also tried to use RegEx, but it didn't work.

The third "solution" I've been thinking about is to use a similar way this post explains
unix . com/shell-programming-scripting/24085-how-get-previous-month-files.html
(I'm sorry, I can't post url formatted, since I'm a new user)
(Calculating the last month, and deleting last month files with mdelete and * wildcard)

Code:

#!/bin/ksh

year=$(date +%Y)
month=$(date +%m)

month=$(($month-1))
if [ $month -lt 1 ]; then
        year=$(($year-1))
        month=12
fi
echo $year$month

But my knowledge is very limited when it comes to linux, and I couldn't make it work. I think it must have something to do with the

Code:

#!/bin/bash

I'm using...

Code:

echo $year$month

If you want the date in the form YYYY-MM , Try:

Code:

printf "%04d-%02d\n" $year $month

Beware. There is a design issue in the script. When there are less days in this month than last month the process will not run for the day numbers which do not exist this month.

You may find it easier to break the process down into separate modules.
1) FTP: Get a directory listing of the remote directory
2) SHELL: Process the directory listing to find files not dated this month
3) FTP: Delete the surplus files (if any are found)
4) FTP: Transfer the new file


Footnote: FTP is not Shell. It knows nothing about regex . Some versions have trouble with complex filenames.