Shell Programming and Scripting

Hi all,

I'm looking to write a script that is dependent upon the existence of 2 files each in separate directories. My thought was to do:
**psuedo code **

execute script
check directory 1 for file1
if file exists then
execute script 2 ( checking directory 2 for file 2)
else
wait 30 min, check directory 1

I suppose I could do this with a loop or a while statement, however, I'm unsure of the exact syntax for the check for file/wait for file statement... and the 30 min delay.

Any help would be appreciated.

P.S. This site is amazing, very informative, and very nicely done!!!

Not putting the whole script ....
But following small snippet may be helpful for you to start with or
expand

Code:

if test -f $dir1/file1
then
 echo "FOUND"
fi

Check the syntax for 'while' for looping.

man sleep for waiting ...

Thanks for the starting point, much obliged.

What if I want to check if the file is there before executing.

if [ $FLAG='y' ]
then
while [ ! -f flag.running ]
do
echo "script is still running ...."
sleep 100
done
else
touch flag.running
${SCR_NAME}.ksh ${PARAM} >${SCR_NAME}.log
fi
rm flag.running

this block will be put in 2 scripts.. which ever script will run first , the other script will have to wait. So i have put the flag .
My question is how to put a while loop to check till when the file is removed .