Shell Programming and Scripting

Hi,

I'm trying to implement nested arrays in ksh.

i've the follwing arrays
SRV=\
"SRV1 "\
"SRV2 "

SRV1=\
"MD11 "\
"MD12 "

SRV2=\
"MD21 "\
"MD22 "

MD11=\
"ABC "

MD12=\
"EFG "

MD21=\
"XYZ "

MD22=\
"PQR "

for i in $SRV
do
echo $i

for j in $i
do
echo $j
done
done


The output of this is
SRV1
SRV1

What i need is the output should be
SRV1
MD11


What its doing is substituting the value of $i in the for loop where as what is actually required is $$i. however this syntax is not acceptable

Can anyone help me out on this as to how to achieve it.

Thanks.

I don't exactly follow you here. But I think you're looking for something like:
eval echo \$$i

Thanks for replying..

I'm pasting the entire code once again.

SRV=\
"SRV1 "\
"SRV2 "

SRV1=\
"MD11 "\
"MD12 "

SRV2=\
"MD21 "\
"MD22 "

MD11=\
"ABC "

MD12=\
"EFG "

MD21=\
"XYZ "

MD22=\
"PQR "

MD11() {
echo "MD11"
}

echo "starting loop $SRV"
cnt=0
for i in $SRV
do
echo "\n$SRV"
srv=\$$SRV
echo $srv
for j in $srv
do
echo "$j"
$j
done
done

The output is as follows :

starting Loop SRV1
$MD11
$MD11

This is where the problem is the last out put line is $MD11.. here its not printing the values contained in the array MD11 but its treating it as a value.
Also when the the call is made to $j it should call the function MD11, since MD11 is stored at the base location of the array, instead it prints
try.sh: $MD11: not found

Request your help.

Instead of
$j
try:
eval $j

Hi,

replacing $j with eval $j results in the $SRV1
However if i replace srv=\$$i with srv=eval $i and then echo $j or eval $j
in both cases the output is SRV1

Thanks,

P.S.
sorry for the confusion but in previous reply i mistyped the output to be $MD11.. its $SRV1. ( In the comments, references to MD11 should be read as SRV1 )

Your posts are so confusing that I am unable to determine whether or not you still have a problem. For the record I meant the function invocation where you have a line that reads
$j
with nothing else at all on the line should perhaps be:
eval $j
I'm not sure if you tried that. It also might be that you need a double eval:
eval eval $j
but then again who knows?