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Shell Programming and Scripting

Bash enumerated types

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# 8  
Old 04-01-2012
Quote:
Originally Posted by kristinu
So one does not use the $ sign for the variables?
Anything that uses bash expressions does not require the $ sign eg:
Code:
let expression
(( expression ))
[[ expression ]]

Anywhere else will eg:
Code:
find . -mtime +$vbLevel
if [ $vbLevel -eq $none ]
case $vbLevel in 
    ($medium) echo yes ;;
esac

# 9  
Old 04-01-2012
Any idea why
Code:
printf "-- Name --"

gives invalid option and how can I make it print without error

---------- Post updated at 07:02 PM ---------- Previous update was at 06:58 PM ----------

Quote:
Originally Posted by Scrutinizer
Indeed. let is an arithmetic evaluation. A synonymous notation would be (ksh/bash):
Code:
(( vbLevel=medium ))

And you can also do this:
Code:
none=0 low=1 medium=2 high=3
vbLevel=2
if (( vbLevel > low )); then
  echo hello
fi

This seems to work. I rather set vbLevel to none, medium, ... and do as below. or is it better using
Code:
(( vbLevel=medium ))

Code:
vbLevel=$medium
if (( vbLevel > low )); then
  echo hello
fi

This works too
Code:
vbLevel=$medium
if [ $vbLevel -gt $low ]; then
  echo hello2
fi

---------- Post updated at 07:10 PM ---------- Previous update was at 07:02 PM ----------

I want to stick with the one below. Would this be ok?
Code:
vbLevel=$medium
if (( vbLevel > low )); then
  echo hello1
fi

---------- Post updated at 07:23 PM ---------- Previous update was at 07:10 PM ----------

I get the user to supply none, low, medium and high from a user option.

Example
Code:
/home/chrisd/srv/sunny/hstmy/bin/bash/raytrac.bash --vblv=high

My code then uses

Code:
vbLevel=$medium
if [ $hasArgument_vbLevel == "true" ]; then
  vbLevel=$value_vbLevel
fi

echo "vbLevel = $vbLevel"

if (( vbLevel > medium )); then
  echo "Hello done"
fi

Thus I replace vbLevel by the user string, which is either none, low, medium or high which then gets associated with the number and then I can do
Code:
if (( vbLevel > medium )); then

---------- Post updated at 07:31 PM ---------- Previous update was at 07:23 PM ----------

I thought to use indirect substitution for this

Code:
vbLevel=${!medium}                    # Indirect substitution
if [ $hasArgument_vbLevel == "true" ]; then
  vbLevel=${!value_vbLevel}        # Indirect substitution
fi

if (( vbLevel > medium )); then
  echo "Hello done"
fi

# 10  
Old 04-02-2012
Quote:
Originally Posted by kristinu
Any idea why
Code:
printf "-- Name --"

gives invalid option and how can I make it print without error
[..]
Try:
Code:
printf "%s" "-- Name --"
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