Shell Programming and Scripting

@Shailesh,

All the rows.

@Corona,

I have already given a code snippet above. You can use that to test.

Regards,
Manu

use this

Code:

sed s:dmp_file_lst:`ls \/opt\/abcd\/efgh\/export_dump\/$DMP_FILE_NM*.dmp | tr "\n" " " `:g

this will replace dmp_file_lst with space separated file names

Posting a program which doesn't do what you want cannot tell us what you do want. The computer can't tell your intent from it, neither can we.

The complete lack of example input and example output makes it even harder to guess. We need to see what success would look like, what you actually want.

Please post some of the input you have, and some of the output you want -- not the bad output, what good output would look like, so we don't have to guess what you want.

Without that, getting the answer you want from anyone is a matter of pure luck.

True. But I need to print in seprate lines, not space seprated (as it will disorder formatting)

Any other idea???

Thanks.

it's very unclear what outcome you desire, unless you provide info as asked by @Corona688

Hmmm, ok.

I have a directory structure like below:

a/b/c

Code:

mkdir -p /a/b/c

inside that there are many files like:

d1
d2
d3
d4

Code:

touch d1 d2 d3 d4

Create a file unix_test, give execute permissions and put the below in it:

Code:

#!/bin/sh

sed "
   s/dmp_file_nm/abc.dmp/g
   s:dmp_file_lst:`ls -1 \/a\/b\/c\/d*`:g
   s/log_file_nm/xyz.log/g" unix_a > unix_b

create another file unix_a and put the following:

Code:

dmp_file_nm
dmp_file_lst
log_file_nm

After executing unix_test, desired output is:

Code:

abc.dmp
d1
d2
d3
d4
xyz.log

Please help me to achieve the same.

Thanks for your suggestions and concerns.

change your 2.line to this

s:dmp_file_lst:`ls -1 \/a\/b\/c\/d*`:g to

Code:

 s/dmp_file_lst/$(ls -1 /a/b/c/d*|sed 's/.*\///;'|sed ':a;N;s/\(.*\)\n\(.*\)/\1\\n\2/;ta')/

regards
ygemici