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If expression syntax

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# 1  
Old 03-29-2012
If expression syntax
Hello there!

I am having some difficulties in the syntax of a script.
I am a newbie Smilie

What i want is a script that copies 1 or more files to a destination folder with
a question if file allready exists

Code:
if ($#argv > 2) then 
	if (-d $argv($#argv)) then
		foreach x ($*)
		cp -i $x to $argv($#argv)
		end
	else
	echo "Usage:  -> $0 file(s) Directory"
	endif
endif


That's the code..

Thanks in advance Smilie
Last edited by Scrutinizer; 03-29-2012 at 10:35 AM.. Reason: Please Use [code] tags [/code], instead of [quote] [/quote] tags, thank you..
# 2  
Old 03-29-2012
Does it have to be csh?
# 3  
Old 03-29-2012
Yes unfortunatelly


I tried slightly different syntax with no luck

Code:
if ($#argv > 2) then 
	if (-d $argv($#argv)) then
		foreach x ($*)
			if (-f $x) cp -i $x $argv($#argv) 
		end
	else echo "Usage: $0 file1 file2 OR $0 file(s) dir"
	endif
else
	echo "Usage:  $0 file(s) Directory"
endif

Moderator's Comments:
Mod Comment You were asked to use code tags instead of quote tags - check your PMs for a guide, thanks.
Last edited by zaxxon; 03-29-2012 at 11:06 AM.. Reason: code tags, see PM
# 4  
Old 03-29-2012
Square brackets for your array index ($argv[$#argv]).
This User Gave Thanks to CarloM For This Post:
ennui92
# 5  
Old 03-29-2012
That was the problem indeed..!!
Thanks very much! Brackets!


ps.Next time i ll put code instead of quote on my code Smilie
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