Shell Programming and Scripting

Hi Thanks for the response.

@suhasingale:yeah that's correct but problem is we cannot connect to the other server because it is in different network.
what is my plan is develop a script and execute it first our envrionment and will send the script to the other server owner and ask them to send the out put file after running the same script.from there will compare two files outputs.

@rangarasan: Can we get the count also at the end to get an idea of the how many files are present in the perticular directory.

ok - I understand now. You will have to write a script to compare two file in two ways then.

Yes, You can

Try this one,

Code:

#! /usr/bin/bash
if [ $# -ne 2 ];then
echo "Usage: $0 [location] [outputfile]";
exit;
fi
dir=$1
output=$2
filecnt=0
dircnt=0
cd $dir
rm $output
for i in `find $dir -name "*"`
do
    if [ -d "$i" ];
    then
        echo "DIR:$i" >>$output
        let dircnt++
        continue
    fi
    echo $i >>$output
    let filecnt++
done
echo "File Count:$filecnt" >>$output
echo "Directory Count:$dircnt" >>$output

Cheers,
Ranga

Hi.

If your system has rsync, I'd use that in the dry-run mode. That would tell what would need to be changed to put the directories in sync. That may or may not be a sufficient report for your purposes, but it would be relatively easy to do (although there is a myriad of available options for rsync) , and could be used as a source for comparison if you had to write a script.

Ir was not installed by default on one Solaris 10 (386) system that I use, but it was on an OpenIndiana box.

Otherwise, it seems to me that you'd need to send data back in a kind of skeleton form, which would describe the directory structure, along with a checksum of the files, and do the compare based on the checksums calculated for the local files ... cheers, drl