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String replace that has spaces

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# 8  
Old 03-23-2012
string replace that has spaces
wow...thank you again for your patience and ideas.

while the last idea works from the command line, on my solaris 8 server, changing the /g to /2g, or /g to /2 (since I want the 2nd pattern in the file to be changed) throws no error, and the pattern in the file is not changed.

the errors thrown from the previous idea to this are here, as is the command used:

Code:
printf "Use SSL=                0;                      REG_DWORD\nSomething\nUse SSL=                0;                      REG_DWORD\nUse SSL=                0;                      REG_DWORD\n" | awk '/Use SSL= *0 *; *REG_DWORD/ && ((++N==2) { sub(/0/, "0x1"); } 1' rf > rf2

ld.so.1: printf: fatal: libiconv.so.2: open failed: No such file or directory
awk: syntax error near line 1
awk: bailing out near line 1
ksh: 11696 Killed

Last edited by methyl; 03-23-2012 at 02:06 PM.. Reason: please use code tags
# 9  
Old 03-23-2012
I think that the awk needs to be nawk on your system.



As for the sed idea we just need an expert to advise how to change only the second occurance of the string.

For my benefit, how big is each file?

Reference post #3. What exactly and precisely defines the second occurance of the string? Is it an exact match for the whole line (including all space characters) or a fuzzy match where the number of space characters varies? We need a better definition of the problem, complete with sample input data and matching expected output data.
Last edited by methyl; 03-23-2012 at 02:21 PM..
# 10  
Old 03-23-2012
string replace that has spaces
This is exactly the contents of the file (the edit post is taking out the extra spaces, in this problem there are 10 spaces between SSL= and 0;, and 15 spaces between 0; and REG_DWORD):

Code:
Use SSL=          0;               REG_DWORD
Use SSL=          0;               REG_DWORD

The expected result is as follows:

Code:
Use SSL=          0;               REG_DWORD
Use SSL=          0x1;            REG_DWORD

Maintaining the format of each line.
Last edited by methyl; 03-23-2012 at 06:34 PM.. Reason: please use code tags then we can see the space characters! Now please re-edit the post so the format is consistent.
# 11  
Old 03-23-2012
Still not clear to me. Lines with different amount of spaces, but otherwise identical values, are they considered equal?
Code:
/usr/xpg4/bin/awk '++A[$1,$2,$3,$4]==2{sub("0;","0x1;")}1' infile

or unequal?
Code:
/usr/xpg4/bin/awk '++A[$0]==2{sub("0;","0x1;")}1' infile

Is it for every line (above) or only for lines that start with "Use SSL=" ?
Code:
/usr/xpg4/bin/awk '/^Use SSL=/ && ++A[$1,$2,$3,$4]==2{sub("0;","0x1;")}1' infile

and
Code:
/usr/xpg4/bin/awk '/^Use SSL=/ && ++A[$0]==2{sub("0;","0x1;")}1' infile

respectively...

And is it only the 2nd occurrence that needs the replacement (like above) and not the 3rd, 4th and 5th, or do they? (in that case then use A[..]++ instead of ++A[..]==2 ). Otherwise please post a larger proper sample of you input file with several lines and the desired output...
Last edited by Scrutinizer; 03-27-2012 at 04:15 AM.. Reason: Added spaces for clarity..
# 12  
Old 03-26-2012
SOLVED: string replace that has spaces
There are few words of praise...brilliant...thank you very much.

The goal being to only change the 2nd instance of the pattern (that begins with "Use SSL=" was solved using either of these commands:

Code:
/usr/xpg4/bin/awk '/^Use SSL=/&&++A[$1,$2,$3,$4]==2{sub("0;","0x1;")}1' infile

and

Code:
/usr/xpg4/bin/awk '/^Use SSL=/&&++A[$0]==2{sub("0;","0x1;")}1' infile


Can you reply with an explanation on what is happening here? Why is /usr/xpg4/bin/awk used? What does the &&++A do? The [$0]? The ==2?, and the 1?
Last edited by Scrutinizer; 03-26-2012 at 04:06 PM.. Reason: Code tags
# 13  
Old 03-26-2012
Hi, /usr/xpg4/bin/awk is used because you mentioned you are on Solaris 8 and the standard awk is either broken or ancient, any case it usually not functioning as expected, whereas /usr/xpg4/bin/awk adheres to POSIX specification...

/^Use SSL=/&&++A[$0]==2 means if a line starts with "Use SSL=" and it is the second time that the same line ($0 means the entire line) is encountered, then:
{sub("0;","0x1;")} substitute "0;" by "0x1;" but otherwise leave the line intact.
1 Perform the default action, which is {print $0}, i.e. print the record...
# 14  
Old 03-26-2012
string replace that has spaces
Thanks.

I've never seen &&++A, how is that defined?

How is that different from:

++A[$1,$2,$3,$4]==2

Very interesting actions.
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