Shell Programming and Scripting

Hello,

I wrote a script that will be run in background and echo some status information from time to time.
after the loop and output I want to get back to prompt automatically.
currently I have to press return to see prompt again. is this possible to do?

can you write contents of script here?

Code:

#!/bin/bash
loopy=1
while [ "$loopy" -eq 1 ]
do
  cnt=0
  $( [ create logfile ] )
  while read logline
  do
    chk=$( less $log | grep $logline )
    if [ "$chk" == "" ];then
      echo "change: " $logline
      cnt=`expr $cnt + 1`
    fi
  done < $logfile
  sleep x
  cp $logfile $log
  if [ "$1" == "" ];then
    break
  fi
  [ back to prompt please ]
done
if [ "$cnt" -gt 0 ]; then
  cp $log $bklog
fi

you want to exit script in while ,it is true ?
yo can try add "exit" in if loop instead of "break"

no, the loop should go on - but -
after calling 'echo' the prompt in shell I'm working in is gone.
if I type 'return' prompt is back. possible to send this keycode from inside of the script?

What are you typing to run this script?

Where does the value of $log and $logline and $1 come from ?

What is the script intended to do? It contains too many issues to guess.

cko 1 & to run in background with endless loop (without 1st parameter to run just 1 time)

oh, sorry - didn't put the whole script in here. logvariables are defined - filenames

script creates "image" of something and stores it in $log on 1st run.
inside of the loop new image is created to $logfile and "compared" to previously created one.
changes should immediately printed out with 'echo' (maybe security issues).