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Reformatting data in matrix form

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# 1  
Old 03-20-2012
Reformatting data in matrix form
Hi,

Some assistance with respect to the following problem will be very helpful.
I want to reformat my dataset in the following manner for subsequent analysis.

I have first column values (which repeat for each value of 2nd column) which are names, the second column specifies position ad the third column is
the 1st value, fourth column is 2nd value. I want to put the names as column headers and the values for a particular position as the value of the 4th column in the input. In case of missing record, it should take the value of the third column of any record for that position.

For example in the input dataset, A through D are the names and C does not occur for pos2, and B,C,D does not occur for pos3. So the value of C for pos2 will be taken from the tird column of any record for pos2 which is 9 (third column is constant for a particular pos ). For pos3, only B will have value 9 while A, C and D will have 7 (third column for pos3).

For the record, I have 80 names and 15677899 records in my actual dataset.


Input


Code:
A pos1 1 2
B pos1 1 3
C pos1 1 4
D pos1 1 5
A pos2 9 6
B pos2 9 7
D pos2 9 8
B pos3 7 9


Expected output

Code:
       A B C D
pos1   2 3 4 5
pos2   6 7 9 8
pos3   7 9 7 7

Last edited by newbie83; 03-20-2012 at 01:33 PM..
# 2  
Old 03-20-2012
I have a way to do this, but it will need to be told what the columns are, since it can't go backwards and insert the first line after it's collated everything.

Code:
$ cat rotarr.awk

BEGIN {
        if(!COLS)       COLS="|A|B|C|D"

        split(COLS, C, "|");
        for(N=2; C[N]; N++)     printf("\t%s", C[N]);
        printf("\n");
}

!LASTROW { LASTROW=$2 }

$2 != LASTROW {
        printf("%s", LASTROW);
        for(N=2; C[N]; N++)
        {
                if(!DATA[C[N]]) DATA[C[N]]=DEF;
                printf("\t%s", DATA[C[N]]);
        }

        printf("\n");
        for(X in DATA)  delete DATA[X];
        LASTROW=$2
}

{
        DATA[$1]=$4
        DEF=$3
}

END {
        printf("%s", LASTROW);
        for(N=2; C[N]; N++)
        {
                if(!DATA[C[N]]) DATA[C[N]]=DEF;
                printf("\t%s", DATA[C[N]]);
        }

        printf("\n");
        for(X in DATA)  delete DATA[X];
}

$ awk -v COLS="|A|B|C|D" -f rotarr.awk data

        A       B       C       D
pos1    2       3       4       5
pos2    6       7       9       8
pos3    7       9       7       7

$

This User Gave Thanks to Corona688 For This Post:
newbie83
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