Shell Programming and Scripting

Hi,
I am stuck with an problem and want some help, what i want to do is

There is a directory name temp
which include file named t1.txt, t2,txt, t3.txt and so on.

These files contains data, but there are some bad character also that is % present in the files , I want to write the script which should open the files present in a directory one by one and if that character found delete it.

I should give that bad character during call of the script
eg ./scriptname .sh % OR ./scriptname.pl %

Thanks

Quick and dirty Perl solution, you should:

Code:

perl -e '@filenames=glob("./*.txt");
for $filename (@filenames){
    open($file ,"<",$filename);
    open ($temp,">","temp.dat");
    while(<$file>){
        $_=~s/$ARGV[0]//g;
        print $temp $_;
    }
    close $file;
    close $temp;
    rename "temp.dat", $filename;
}' %

This is a single line command any script if possible
This will a extra file which is not needed.

Thanks

Code:

perl -npi.bak -e 'BEGIN{$sep=shift;}s/$sep//g;' % *.txt

But again a regex special character could make this behave in an unexpected fashion.

But this too make an extra file like a1.txt.bak, This file do not wanted

Remove '.bak' from that one-liner.

The UNIX Guru is back

---------- Post updated at 10:54 AM ---------- Previous update was at 10:52 AM ----------

After removing also the .bak file is forming