Shell Programming and Scripting

Hi,

I want to extract one value/column from a ps -ef command. Here's an example of the output:

mqm 14552 1 0 15:48:43 - 0:00 amqpcsea SWNETTQ1
mqm 57082 1 0 15:48:42 - 0:00 amqpcsea SWNETDQ1
mqm 88104 1 0 15:26:37 - 0:00 amqpcsea SWNETEQ1
mqm 90196 1 0 16:03:56 - 0:00 amqpcsea SWNETTQ2

I want to display only the last column like this

SWNETTQ1
SWNETDQ1
SWNETEQ1
SWNETTQ2


I can do this using the following command but it seems a bit cumbersome:

ps -ef|grep sea|grep -v grep|cut -f2 -d"-"|cut -f2 -d":"|cut -f3 -d" "

Anyone know of a better way to do this? I've tried awk but have only managed to get them displayed on the same line

thanks

Gareth

ps -ef | nawk '/sea/ { print $NF}'

also works ...

Code:

ps -ef | awk '/sea/ {print $NF}'

thanks for those, they both worked a treat although I did still need to keep the greps in there otherwise the results were like this:

awk
===
# ps -ef | awk '/sea/ {print $NF}'

SWNETTQ1
$NF}
SWNETDQ1
SWNETEQ1
SWNETTQ2

# ps -ef |grep sea| awk '/sea/ {print $NF}'

SWNETTQ1
sea
SWNETDQ1
$NF}
SWNETEQ1
SWNETTQ2

nawk
====
# ps -ef | nawk '/sea/ {print $NF}'

SWNETTQ1
SWNETDQ1
$NF}
SWNETEQ1
SWNETTQ2

ps -ef |grep sea| nawk '/sea/ {print $NF}'

SWNETTQ1
SWNETDQ1
$NF}
sea
SWNETEQ1
SWNETTQ2

However, including (and adjusting) the greps removed the erroneous entries.
# ps -ef |grep amqpcsea|grep -v grep| awk '/sea/ {print $NF}'

SWNETTQ1
SWNETDQ1
SWNETEQ1
SWNETTQ2


Thanks again

this may work as well ...

Code:

ps -ef | awk '/sea/ && $NF !~ /\$/ {print $NF}'

Code:

ps -ef|grep sea|grep -v grep|cut -d" " -f 9

ps -ef|grep [s]ea|cut -d" " -f 9