Shell Programming and Scripting

hello all!
well, here is my problem:
i have to write a script which waits for a directory as an argument and scans it recuresively and than it prints those files, which have write permission for everyone (as relative path from the argument directory so the find will be the key). and it shouldnt print those files which have write permissions for everyone but they couldnt be writed (their parent directory dont have execution permission for the others)

(sorry for my bad english)

What OS are you on - waiting for a directory can mean a lot of different things depending on the OS. What shell are you using? (like bash, ksh, etc.)

ubuntu and bash

heres a little example

Code:

$ls -lR /home/example 
/home/example: 
total 8 
drwxrwxr-x 2 example users 4096 2009-01-31 00:00 directory1 
drwxrwx--- 2 example users 4096 2009-01-31 00:00 directory2 
-rw-rw-rw- 1 example users    0 2009-01-31 00:00 first.txt 
 
/home/h123456/directory1: 
total 0 
-rw-rw-rw- 2 example users    0 2009-01-31 00:00 aaa.txt 
-rw-rw-r-- 2 example users    0 2009-01-31 00:00 bbb.txt 
 
/home/h123456/directory2: 
total 0 
-rw-rw-rw- 2 example users    0 2009-01-31 00:00 ccc.txt 

$ ./prog.sh /home/example
first.txt 
directory1/aaa.txt

Exactly what you mean by 'waiting for a directory' is still unclear. Assuming that as soon as a directory exists, all files below are present, might not be wise, or correct, and thus the results of a search at time t might not be the same as a search at time t+n.

Assuming the directory exists, and is in a stable/steady state, this will find the files you are looking for. It should handle filenames with spaces, but will not handle directory names with spaces. The other assumption is that all directories/files below a directory that has an executable bit turned off for the world (other) excludes it, and anything below it, from the search.

Code:

dname="${1:-.}"
while [[ ! -d $dname ]]    # simple wait for the directory to exist -- may not be enough to be correct
do
    sleep 10
done

find $dname -ls | awk '
    {
        split( $3, perms, "" );

        if( dname && index( $11, dname ) == 1 )
            next;
        else
            dname = ""

        if( perms[1] == "d" )
        {
            if( perms[10] == "-" )      # execute for directory is off for world, can be skipped
                dname = $11 "/";
        }
        else
            if( perms[9] == "w" )
                print;
    }
'

forget that waiting for the directory thing, i just want to say that i have to specify a directory as an argument when i execute it.

and i forget that, i have to make it without awk :S

It certainly would have been nice to have had all parameters and/or limitations in your initial post.

With the 'no awk' requirement this seems more like a homework assignment than not. Maybe, before anybody else spends time crafting a solution, you should indicate whether it's a homework assignment or not.

its a simple homework :S

---------- Post updated at 12:30 PM ---------- Previous update was at 12:24 PM ----------

well, sorry for the misinformation again,
my mate just told me our teacher let us use awk