Shell Programming and Scripting

Hi falks,

I have the following ksh function ,which adding entry to crontab during ksh program running:
{
print "Go\c" >/dev/null 2>&1
print '0 0 * * * su - ias -c "/home/orca/core-${SCHEMA_NAME}/CLI/cleanup_BRMS.ksh"\c' >/dev/null 2>&1
print "\033:wq!" >/dev/null 2>&1
} | \crontab -e >/dev/null 2>&1

The problem with this function that the parameter ${SCHEMA_NAME} was not substituted with the real value.
The crontab got the following entry:
0 0 * * * su - ias -c "/home/orca/core-${SCHEMA_NAME}/CLI/cleanup_BRMS.ksh

my question:
1. Why the parameter was not substituted with a value?
2. Is there another way to insert values into crontab during running of ksh program?

Thanks in advance,
Nir

1. your print statement used single quotes which made it print literal ... use this instead ...

Code:

print "0 0 * * * su - ias -c /home/orca/core-${SCHEMA_NAME}/CLI/cleanup_BRMS.ksh\c"

2. edit a copy of outfile of "crontab -l" then make the edited copy the crontab by "crontab $tmpfile"

Hi Just Ice,

Thanks!

Eventually,i used your suggestion with a little change:
print "0 0 * * * su - orca -c \"/home/orca/core-${SCHEMA_NAME}/CLI/cleanup_BRMS.ksh\"\c >/dev/null 2>&1

because the final result in the crontab should be as the following:
0 0 * * * su - ias -c "/home/orca/core-<schema name>/CLI/cleanup_BRMS.ksh"

Best regards,
Nir